Ok, again posting after a long time.
Predict the output of the following code, the contains 3 sets of function calls, each set contains one call by value and one by reference, but the object being passed everytime is a reference type. It is recommended that you do not run the code, just predict the output.
StringBuilder used in the code is a class and is a reference type.
Also explain your answers.
class Class1
{
static void Main(string[] args)
{
StringBuilder str;
// Set 1
str = new StringBuilder(“Types”);
CrazyFunction1(str);
Console.WriteLine(str.ToString());
str = new StringBuilder(“Types”);
CrazyFunction2(ref str);
Console.WriteLine(str.ToString());
// Set 2
str = new StringBuilder(“Types”);
CrazyFunction3(str);
Console.WriteLine(str.ToString());
str = new StringBuilder(“Types”);
CrazyFunction4(ref str);
Console.WriteLine(str.ToString());
//Set 3
str = new StringBuilder(“Types”);
CrazyFunction5(str);
Console.WriteLine(str.ToString());
str = new StringBuilder(“Types”);
CrazyFunction6(ref str);
Console.WriteLine(str.ToString());
Console.ReadLine();
}
private static void CrazyFunction1(StringBuilder x)
{
x = null;
}
private static void CrazyFunction2(ref StringBuilder x)
{
x = null;
}
private static void CrazyFunction3(StringBuilder x)
{
x.Append(” are crazy”);
}
private static void CrazyFunction4(ref StringBuilder x)
{
x.Append(” are crazy”);
}
private static void CrazyFunction5(StringBuilder x)
{
x = new StringBuilder(“crazy”);
}
private static void CrazyFunction6(ref StringBuilder x)
{
x = new StringBuilder(“crazy”);
}
}
